Question

solve this equation :- 1/5(2x+1) - 1/3 (x-2)=x - 24⅓. only for moderators and stars.
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Answer 1

Answer:

• 27

Explanation :

Given equation,

$\implies \dfrac{1}{5} (2x + 1) - \dfrac{1}{3} (x - 2) = x - 24 \frac{1}{3}$

Solving for $x$

$\implies \dfrac{2x + 1}{5} - \dfrac{x - 2}{3} = x - \frac{73}{3}$

$\implies \dfrac{3(2x + 1) - 5(x - 2)}{15} = \dfrac{3x - 73}{3}$

$\implies \dfrac{6x + 3 - 5x + 10}{15} = \dfrac{3x - 73}{3}$

$\implies \dfrac{x + 13}{15} = \dfrac{3x - 73}{3}$

$\implies 3(x + 13) = 15(3x - 73)$

$\implies 3x + 39 = 45x - 1095$

$\implies 39 + 1095 = 45x - 3x$

$\implies 1134 = 42x$

$\implies\dfrac{1134}{42} = x$

$\implies 27 = x$

The value of x is 27

Answer 2

$\sf{ \underline \green{Given \: equation \: : }}$

$\rightarrow \: { \frac{1}{5} (2x + 1) - \frac{1}{3} (x - 2) = x - 24 \frac{1}{3} }$

$\sf{ \underline \green{Solution \: :}}$

$\large\sf{ \qquad : \implies \frac{2x + 1}{5} - \frac{x - 2}{3} = x - \frac{73}{3} }$

$\large \sf{ \qquad : \implies\frac{3(2x \: + \: 1) \: - \: 5(x \: - \: 2)}{15} = \frac{3x \: - \: 73}{3} }$

$\large\sf{ \qquad : \implies \: \frac{6x \: + \: 3 \: - \: 5x \: + \: 10}{15} = \frac{3x - 73}{3} }$

$\large\sf{ \qquad : \implies \: \frac{x + 13}{15} = \frac{3x - 73}{3} }$

$\sf{ \qquad : \implies \: 3 \: (x + 13) = 15(3x - 73)}$

$\sf{ \qquad : \implies \: 3x + 39 = 45x - 1095}$

$\sf{ \qquad : \implies \: 39 + 1095 = 45x - 3x}$

$\sf{ \qquad : \implies \: 1134 = 42x}$

$\sf{ \qquad : \implies \: x = \cancel \frac{1134}{42} }$

$\sf{ \qquad : \implies \: x = 27}$