Math, asked by kavithaullash, 1 year ago

solve this equation

1-[x-2]-[(x-3)-(x-1)]=0

Answers

Answered by reyoudy

1

Step-by-step explanation:

1-(x-2)-[(x-3)-(x-1)]=0

1-(X-2)-(-2)=0

1-x+2+2=0

1+2+2=x

x=5

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