Question

Solve this equation.

Answer 1

Sigma( K =4 to 143 ) { 1/( √k + √(K+1))}

put K = 4 → 1/( √4 + √5 ) = √5 -√4
K= 5 → 1/( √5 + √6 ) = √6 - √5
K = 6→ 1/( √6 + √7) = √7 -√6
.................
...........
K = 143→ 1/( √143 +√144) = √144 -√143

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add all of these ,

e.g

( √5- √4) + (√6 -√5)+ ( √7-√6) .......(√144-√143) = -√4 + √144 = 12 - 2 = 10

10 = a -√b

10 - √0 = a -√b

a = 10 and b = 0