Question

Solve this equation.
13(y+7)=3(y−1).​

Answer 1

$:\implies\sf{}3m - 5 = 2m+ \dfrac{1}{3}$

$:\implies\sf{}3m - 2m = \dfrac{1}{3} + 5$

$:\implies \sf{}m = \dfrac{1}{3} + 5$

$:\implies \sf{}m = \dfrac{ \frac{1 \times 3}{3} + \frac{5 \times 3}{1} }{3}$

$:\implies \sf{} m = \dfrac{1 + 15}{3}$

$:\implies \star \underline{\boxed{ \sf{}m = \dfrac{16}{3} }}\star$

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Answer 2

Answer:

13(y+7) = 3(y-1)

13y+91 = 3y-1

13y-3y = -1-91

10y = -90

y = -90/10

= -9

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