Question

Solve this equation : 2t2 + t = 1​

Answer 1

Answer:

2

2

+

=

1

2t^{2}+t=1

2t2+t=1

Factor

1

Move terms to the left side

2

2

+

=

1

2t^{2}+t=1

2t2+t=1

2

2

+

−

1

=

Answer 2

Answer:

The roots of the given quadratic equation are t = - 1 or t = 1 / 2.

Step-by-step-explanation:

The given quadratic equation is 2t² + t = 1.

We have to find the roots of the quadratic equation.

Now,

2t² + t = 1

⇒ 2t² + t - 1 = 0

⇒ 2t² + 2t - t - 1 = 0

⇒ 2t ( t + 1 ) - 1 ( t + 1 ) = 0

⇒ ( t + 1 ) ( 2t - 1 ) = 0

⇒ ( t + 1 ) = 0 OR ( 2t - 1 ) = 0

⇒ t + 1 = 0 OR 2t - 1 = 0

⇒ t = - 1 OR 2t = 1

⇒ t = - 1 OR t = 1 / 2

∴ The roots of the given quadratic equation are t = - 1 or t = 1 / 2.