Question

Solve this equation
2x+3y-2=0
5x-3/2y-2=0

Answer 1

Answer :

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Answer 2

Answer:

$\frac{1}{2}$ and $\frac{1}{3}$ are the required value of x and y.

Step-by-step explanation:

Explanation:

Given that, 2x + 3y -2 and 5x - $\frac{3y}{2}$ - 2 = 0

We solve this equation by using elimination.

• The elimination method involves removing a variable from a system of linear equations by employing addition or subtraction along with multiplication or division of the variable coefficients.

Step 1:

From the question we have,

2x + 3y -2  .........(i)

and 5x - $\frac{3y}{2}$ - 2 = 0

⇒10x - 3y - 4 = 0 ........(ii)

Now, by elimination method

2x + 3y = 2

10 x -3y = 4  

12x = 6

⇒x = $\frac{6}{12}$ = $\frac{1}{2}$

Now, we put the value in (1) we get,

2 ($\frac{1}{2}$) + 3y = 2

⇒1 + 3y = 2

⇒ 3y = 2 -1 = 1

⇒ y =  $\frac{1}{3}$

Final answer:

Hence, $\frac{1}{2}$ and $\frac{1}{3}$ are the required value of x and y.

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