Question

solve this equation​

Answer 1

Required Solution:-

Given:

• abx² + (b² - ac)x - bc = 0

To find:

• The values of x.

Solution:

Quadratic equations are solved by splitting the middle term and then factoring out and finally solved by using zero product rule. We will do the same thing here.

➡ abx² + (b² - ac)x - bc = 0

➡ abx² + b²x - acx - bc = 0

Now, factor out by taking the common factor.

➡ bx(ax + b) - c(ax + b) = 0

Now, take (ax + b) as common,

➡ (ax + b)(bx - c) = 0

By zero product rule,

Either (ax + b) = 0 or (bx - c) = 0

So,

➡ ax + b = 0

➡ x = -b/a

Again,

➡ bx - c = 0

➡ x = c/b

Hence,

x = -b/a, c/b

Answer:

• x = -b/a, c/a

Answer 2

Answer:

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