Solve this equation:- 3x-1/5-x/7=3
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The above question can be written as, ⇒[(7×(3x−1))−(5×(x))/35]=3 [Taking L.C.M of 5 and 7]
⇒((21x−7)−(5x))/35=3
⇒(21x−7−5x)/35=3
⇒(16x−7)/35=3...[Multiplying both side by 35]
⇒[(16x−7)/35]×35=3×35
⇒16x−7=105
⇒16x=105+7
⇒16x=105+7
⇒16x=112...[Multiplying both side by 1/16]
⇒16x×(1/16)=112×(1/16)
⇒x=7
By substituting 7 in the place of x in given equation, we get
LHS,
=(16x−7)/35
=((16×7)−7)/35
(112−7)/35
=(105/35)
=3
RHS,
=3
By comparing LHS and RHS
⇒(4/3)=(4/3)
∴LHS=RHS
Hence, the result is
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