Math, asked by agarwalb059, 28 days ago

solve this equation: 3y/10+2y/5=7y/25+29/25

Answers

Answered by BoldStyle
85

3y/10 + 2y/5 = 7y/25 + 29/25

3y/10 + 2y/5 - 7y/25 = 29/25

( 3y x 5 + 2y x 10 - 7y x 2 ) / 50 = 29/25

( 15y + 10y - 14y ) / 50 = 29/25

11y / 50 = 29/25

Cross multiplying

11y x 25 = 29 x 50

275y = 1450

y = 1450/275

y = 58/11

Answered by hareem23
3

 \huge \mathbb \red{ANSWER: }

3y/10 + 2y/5 = 7y/25 + 29/25

3y/10 + 2y/5 - 7y/25 = 29/25

(3y x 5 + 2y x 10 - 7y x 2/50 = 29/25

(15y + 10y - 14y) / 50 = 29/25

11y/50 = 29/25

Cross multiplying

11y x 25 = 29 x 50

275y = 1450

y = 1450/275

y = 58/11

Similar questions