Question

solve this equation ​

Answer 1

Answer:-------

$\frac{7}{x} + 35 = \frac{1}{10} \\ = > \frac{7}{x} = \frac{1}{10} - 35 \\ = > \frac{7}{x} = \frac{1 - 350}{10} \\ \frac{7}{x} = \frac{ - 349}{10} \\ cross \: multiplication \\ x \times ( - 349) = 70 \\ = > x = \frac{70}{ - 349}$

Answer 2

$\huge \tt { \underline{ \underline{Solution:-}}}$ $\frac{7}{x} + 35 = \frac{1}{10} \\ \\ \\ \implies \: \frac{7}{x} = \frac{1}{10} - 35 \\ \\ \\ \implies \: \frac{7}{x} = \frac{1 - 350}{10} \\ \\ \\ \implies \frac{7}{x} = \frac{ - 349}{10} \\ \\ \\ \implies \: x = \frac{ - 7 \times 10}{349} \\ \ \\ \ \implies \: x = \frac{ - 70}{349}$

$\sf \: Verifcation \:L. H. S \\ \ \\ \ \implies \frac{7}{x} + 35 \\ \\ \\ \implies \: y - \frac{7}{ \frac{ - 70}{349} } + 35 \\ \ \\ \ \implies \: \frac{ - 349}{10} + 35 \\ \\ \\ \implies \: \frac{ - 349 + 350}{10} = \frac{1}{10} \\ \ \\ \ \implies \: R. H. S$