Solve this equation,
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Answer:
a
2
x
2
+(ax
2
+1)x+a=a
2
x
2
+ax
3
+x+a
=ax
2
(a+x)+1(a+x)
=(ax
2
+1)(a+x) this was the answer of 31
ab(x
2
+1)+x(a
2
+b
2
)
=abx
2
+ab+a
2
x+b
2
x
=abx
2
+a
2
x+ab+b
2
x
=ax(bx+a)+b(bx+a)
=(bx+a)(ax+b) answer 32
Factorizingx
2
−(a+b)x+ab,
=x
2
−ax−bx+ab,
=x(x−a)−b(x−a)
=(x−a)(x−b) answer of 33
the last answer
Given : x
2
+
x
2
1
−2−3x+
x
3
We can further write it as
x
2
+
x
2
1
−2−3x+
x
3
=(x−
x
1
)
2
−3(x−
x
1
)
By taking the common terms out
x
2
+
x
2
1
−2−3x+
x
3
=(x−
x
1
)(x−
x
1
−3)
answer 34
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