Question

Solve this equation 7+4√3+1/7+4√3​

Answer 1

Answer:

The required answer is 14.

Step-by-step explanation:

Firstly we have to rationalize the value of 1/(7+4√3).

This is to be done by multiplying both numerator and denominator by (7-4√3).

After rationalisation we will get the value as 7-4√3.

Then evaluating the equation we will get the answer 14.

For full solution refer to the above attachment.

Answer 2

The answer is $7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 18.452$

Given:

The given number is  $7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3}$

To find:

To solve the given equation $7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3}$

Solution:

Simplifying the given terms,

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 7+ \frac{1}{7} + 2 (4 \sqrt{3} )$

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 7+ \frac{1}{7} + 8 \sqrt{3}$  

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = \frac{49+1 }{7} + 8 \sqrt{3}$

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = \frac{50}{7} + 8\sqrt{3}$

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 7.14+ 8\sqrt{3}$

Substituting the value of $\sqrt{3} = 1.414$, we get

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 7.14 + 8 (1.414)$

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 7.14 + 11.312$

$7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 18.452$

Hence the answer is $7 + 4\sqrt{3} + \frac{1}{7} + 4\sqrt{3} = 18.452$

#SPJ2