solve this equation
Answers
1 Simplify brackets.
\frac{4x-2}{3}-\frac{23}{3}=13-5\times \frac{7x+5}{3}
3
4x−2
−
3
23
=13−5×
3
7x+5
2 Factor out the common term 22.
\frac{2(2x-1)}{3}-\frac{23}{3}=13-5\times \frac{7x+5}{3}
3
2(2x−1)
−
3
23
=13−5×
3
7x+5
3 Simplify 5\times \frac{7x+5}{3}5×
3
7x+5
to \frac{5(7x+5)}{3}
3
5(7x+5)
.
\frac{2(2x-1)}{3}-\frac{23}{3}=13-\frac{5(7x+5)}{3}
3
2(2x−1)
−
3
23
=13−
3
5(7x+5)
4 Join the denominators.
\frac{2(2x-1)-23}{3}=13-\frac{5(7x+5)}{3}
3
2(2x−1)−23
=13−
3
5(7x+5)
5 Multiply both sides by 33.
4x-25=39-5(7x+5)4x−25=39−5(7x+5)
6 Expand.
4x-25=39-35x-254x−25=39−35x−25
7 Simplify 39-35x-2539−35x−25 to -35x+14−35x+14.
4x-25=-35x+144x−25=−35x+14
8 Add 2525 to both sides.
4x=-35x+14+254x=−35x+14+25
9 Simplify -35x+14+25−35x+14+25 to -35x+39−35x+39.
4x=-35x+394x=−35x+39
10 Add 35x35x to both sides.
4x+35x=394x+35x=39
11 Simplify 4x+35x4x+35x to 39x39x.
39x=3939x=39
12 Divide both sides by 3939.
x=1