solve this equation.
(a+2)²= 2a+2a+2²+a²
(a+2)²=
Answers
Answered by
20
Answer:
(a+2)²= 2a+2a+2²+a²
=>(a+b)²=a²+b²+2ab
So
(a+2)² = a²+2²+2*a*2
=> (a+2)² = a² + 4a + 4
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Answered by
0
Answer:
As we know that (a+2)^2=a^2+ 4+2a
Then equating the given equation
a^2+ 4+2a=2a+2a+4+a^2
cancelling a^2 & 2a & 4 on both sides
we get,
2a^2=2a
a^2=a
taking a as common
a (a-1)=0
a=0; a=1
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