Question

solve this equation

a bag contains 25 paisa and 50 pais coins whose total value is rupees30 if the number of 25 paisa coin is 4 times that ofb50 paisa coins, find the no. of each type of coin​

Answer 1

let the no. of 25 paise coin be r and no. of 50 paise coin be s. no of 25 coin be 4 times 50 paise it means value of r is 4s

Answer :

25 paise × r + 50 paise × s = 30 rupees

25 paise × 4s + 50s. = 3000 paise

100s + 50s = 3000 paise

150s = 3000 paise

s = 3000/150

s = 20

it means that the no. of the 50 paise coin is 20

no. of 25 paise coin = 20 × 4

= 80

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