Question

Solve this equation & verify your answer :

$\frac{ \frac{2}{5}x + 3}{ \frac{1}{3}x - 1 } = \frac{3}{5}$
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Answer 1

Answer:

3(x−3)=5(2x+1)

⇒  3x−9=10x+5

⇒   3x−10x=5+9

⇒   −7x=14

⇒   −x=714

⇒   x=−2

Step-by-step explanation:

3(x−3)=5(2x+1)

⇒  3x−9=10x+5

⇒   3x−10x=5+9

⇒   −7x=14

⇒   −x=714

⇒   x=−2

Answer 2

Answer:

x = -18

Step-by-step explanation:

Step 1: Cross-multiply.

$\frac{\frac{2}{5} x+3}{\frac{1}{3}x-1 }=\frac{3}{5} \\(\frac{2}{5} x+3)*5=3*(\frac{1}{3}x-1 )\\2x+15=x-3$

Step 2: Subtract x from both sides.

$2x+15-x=x-3-x\\x+15=-3$

Subtracting 15 from both sides.

$x+15-15=-3-15\\x=-18$

Answer:

$x=-18$

Verification:

$\frac{\frac{2}{5}x+3 }{\frac{1}{3}x-1 }=\frac{3}{5}\\ \frac{\frac{2}{5}*(-18)+3 }{\frac{1}{3}*(-18)-1 }=\frac{3}{5}\\ \frac{\frac{-36}{5}+3 }{(-6)-1 }=\frac{3}{5}\\ \frac{\frac{21}{5} }{(-7) }=\frac{3}{5}\\\frac{21}{5}*\frac{1}{-7}=\frac{3}{5}\\ \frac{3}{5} = \frac{3}{5}$

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