Math, asked by chandanpandit252, 9 months ago

Solve this equation by using quadratic formula.​

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Answers

Answered by bhavyagugnani
1

Answer:

= a( x² + 1 ) - x( a² + 1 ) = 0

= ax² + a - x( a² + 1 ) = 0

= ax² - ( a² + 1 )x + a = 0

Here,

A = a , B = -( a² + 1 ) and C = a

= ax² - a²x - x + a = 0

= ax( x - a ) - 1( x - a ) = 0

= ( ax - 1 ) ( x - a ) = 0

= ax - 1 = 0 or x - a = 0

∴ x = 1/a or a

VERIFICATION

∴ α+β - B/A

= 1/a + a = -( -( a² + 1 ) )/ a .

∴ ( 1 + a² )/a = ( 1 + a² )/ a

and,

αβ = C/A

= 1/a × a = a/a

∴ 1 = 1

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