Question

Solve this equation dy/dx-x tan(y-x)=1

Answer 1

Answer:

dydx−x tan(x−y)=1

dydx=x tan(x−y)+1

So you want to know what to do now?

Let's say x−y=t

Taking derivative of both sides…

1−dydx=dtdx

dydx=1−dtdx

Now…

dydx=xtan(x−y)+1

So we can say that

1−dtdx=xtant+1

dtdx=−xtant

dttant=−xdx

Let's Integrate both sides!

∫1tantdt=−∫ xdx