Question

solve this equation fast​

Answer 1

$\huge\fbox{Answer}$

Answer :

D

Solution :

F=qvBsinθ⇒B=fqvsinθF=qvBsinθ⇒B=fqvsinθ

Bmin=FqvBmin=Fqv (when θ=90∘θ=90∘)

∴Bmin=Fqv=10−1010−12×105=10−3tesla∴Bmin=Fqv=10-1010-12×105=10-3tesla

in zˆz^-direction.

Answer 2

Explanation:

1/1000 T in -ve direction.