solve this equation (i)
Answers
Answer:
1 / 1
Step-by-step explanation:
Let the original fraction be x/y
Case 1: Adding 1 to the numerator and Subtracting 1 from the denominator:-
⇒ ( x + 1 ) / ( y + 1 ) = 1 / 1
Cross multiplying we get,
⇒ 1 ( x + 1 ) = 1 ( y + 1 )
⇒ x = y ... ( Eqn 1 )
Case 2: Adding 1 only to the denominator:-
⇒ ( x ) / ( y + 1 ) = 1 / 2
Cross multiplying we get,
⇒ 2 ( x ) = 1 ( y + 1 )
⇒ 2x = y + 1
Substituting the values of x from Eqn ( 1 ) we get,
⇒ 2y = y + 1
⇒ 2y - y = 1
⇒ y = 1
From Eqn ( 1 ) we can say that, x is also equal to 1.
Hence the fraction is x / y = 1 / 1
Let the fraction be x/y
Now acc to que.-
x+1/y-1=1
Or, x+1=1(y-1)
Or x=y-1-1
Therefore x=y-2-----(1)
And x/y+1=1/2-------(2)
Now putting x=y-2 in eq (2) we get,
Y-2/y+1=1/2
Or 2(y-2)=1(y+1) {by cross Multiplying}
Or 2y-4=y+1
Or 2y-y=1+4
Therfore y=5
Now putting y=5 in eq(1) we get,
x=5-2
Therefore x=3
Therfore the required fraction is x/y=3/5
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