Question

SOLVE THIS EQUATION IN CROSS MULTIPLICATION​

Answer 1

${\huge{{\mathtt{\red{ANSWER  :-}}}}}$

refer to the attachment ☆

hope it helps ☆

Answer 2

$\huge{\mathcal{\underline{\underline{AnsWeR \: :- }}}}$

$\huge\bold\pink{ ~♡~ }$ $\huge\colorbox{blue}{ Solution \: :- }$

$\sf\green{ ~✻~}$ $\frac{ 2x }{ 3 } \: { + } \: \frac{ 3y }{ 5 } \: { = } \: { 17 }$ $\huge\red{ ~⇝~}$ ①

$\sf\green{ ~✻~ }$ $\frac{ 3x }{ 4 } \: {+} \: \frac{ 2y }{ 3 } \: {=} \: { 19 }$ $\huge\red{ ~⇝~ }$ ②

$\sf\green{ ~✻~ }$ $\frac{ x } { 9~×~-228~+~8~×~-255 } \: {=} \: \frac{ y }{ -225~×~9~+~-228~×~10 } \: { = } \: \frac{ 1 }{ 10~×~8~-~9~×~9 }$

$\sf\green{ ~✻~ }$ $\frac{ x }{ -2052~+~2040 } \: {=} \: \frac{ y }{ -2295~+~2280 } \: {=} \: \frac{ 1 }{ 80~-~81 }$

$\sf\green{ ~✻~ }$ $\frac{ x }{ 12 } \: {=} \: \frac{ y }{ 15 } \: {=} \: { -1 }$

$\huge\orange{ ~✻~ }$ $\huge\colorbox{pink}{ x ~ = ~ 12 }$

꧁❤•༆$\huge\purple{ AND }$༆•❤꧂

$\huge\orange{ ~✻~ }$ $\huge\colorbox{pink}{ y ~ = ~ 15 }$

$\sf\red{~꧁~}$$\bf\underline\green{darkⓒⓗⓞ©ⓛate}$$\sf\red{~꧂~}$