Question

solve this equation of logarithm log 4 32 equal to x-4

Answer 1

$log_{4}(32) = x - 4 \\ log_{4}( 4 \times 4 \times 2) = x - 4 \\ log_{4}( {4}^{2} ) + log_{4}(2) = x - 4 \\ 2 + \frac{1}{2} = x - 4 \\ x = 6 + \frac{1}{2} = \frac{13}{2}$

Answer 2

Step-by-step explanation:

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