solve this equation
Q no.vii
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((2x+15)/5)/(x-3)/3=3/5
((2x+15)3)/(x-3)5=3/5
(6x+45)/(5x-15)=3/5
(6x+45)5=(5x-15)3
30x+225=15x-45
15x=-270
x=-270/15
x=-18
((2x+15)3)/(x-3)5=3/5
(6x+45)/(5x-15)=3/5
(6x+45)5=(5x-15)3
30x+225=15x-45
15x=-270
x=-270/15
x=-18
Answered by
1
here the answer if i writing the calculation it will be so long. if u don't see clearly then massage me. answer is x=-12
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