Question

solve this equation steb by step
5(4-3c)-3(c+2)

Answer 1

Answer:

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Answer 2

Answer:

5(4-3c)-3(c+2)=0

20-15c -3c-6=0

-15c-3c+20-6=0

-18c+14=0. --------->eq 1

-18c=-14

C= 14/18

C=7/9 ----------------> c value

-18c+14=0 -----------> in eq 1 applied by c value

-18(7/9)+14=0

-2(7)+14=0

-14+14=0

0=0

hence its proved