Question

solve this equation tan theta equals -1/square toot 3 for [0degrees,360degrees].

Answer 1

Answer:

$\tan \alpha = - \frac{ 1}{ \sqrt{3} } \\ > \tan\alpha = \tan(2 \times \frac{\pi}{2} - \frac{\pi}{6} ) \: or \: \tan(4 \times \frac{\pi}{2} - \frac{\pi}{6}) \\ > \alpha = (2 \times \frac{\pi}{2} - \frac{\pi}{6} ) \: or \: (4 \times \frac{\pi}{2} - \frac{\pi}{6} ) \\ > \alpha = (\pi - \frac{\pi}{6} ) \: or \: (2\pi - \frac{\pi}{6} ) \\ > \alpha = (\frac{6\pi - \pi}{6} ) \: or \: ( \frac{12\pi - \pi}{6} ) \\ > \alpha = \frac{5\pi}{6} \: or \: \frac{11\pi}{6}$

so the required value is 5π/6 and 11π/6

which is 150° and 330°