Question

solve this equation:
$3(x - 1) \leqslant \frac{1}{2} (x + 1) - 6$
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Answer 1

Step-by-step explanation:

$3(x - 1) \leqslant \frac{1}{2} (x + 1)- 6 \\ 3x - 3 \leqslant \frac{1}{2} x + \frac{1}{2} - 6 \\ 3x - \frac{1}{2} x \leqslant \frac{1}{2} - 6 + 3 \\ \frac{6x - x}{2} \leqslant \frac{1 - 12 + 6}{2}$

$\frac{5x}{2} \leqslant - \frac{5}{2} \\ x \leqslant - 1$

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