Math, asked by tripathiaradhana33, 6 months ago

solve this equation using cross multiplication method
plz help ​

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Answers

Answered by nazrulislam69971
0

3x+2y=10 and 4x−2y=4

Step-by-step explanation:

3x+2y=10 and 4x−2y=4

Answered by aryan073
4

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

 \:  \:   \bigstar \large  \green{ \bold{ \underline{ \underline{ \:answer \: }}}}

 \:  \:  \underline {\bf{ \color{orange}given :}}

 \:  \\  \implies \displaystyle \sf \frac{(2m + 5) - (4m - 3)}{(3m - 1) - (2m + 9)}  =  \frac{ - 54}{69}

 \:  \:  \large \green{ \bold{ \underline{ \underline{step \: by \: step \: \: explaination}}}}

 \:  \:  \:  \:  \:  \:  \:    \displaystyle\tt:  \implies  \frac{(2m + 5) - (4m - 3)}{(3m - 1) - (2m + 9)}  =  \frac{ - 54}{69}

 \: \:  \:  \:  \: \:  \:   \:   \displaystyle \tt : \implies \: \:  \frac{(2m + 5 - 4m + 3)}{(3m - 1 - 2m - 9)}  =  \frac{ - 54}{69}

 \:  \:  \:   \:  \:  \:  \:  \: \:  \displaystyle \tt   :   \implies \:  \frac{( - 2m + 8)}{(m - 10)}  =  \frac{ - 54}{69}

 \:  \:  \:  \:   \\ \:  \:  \:  \:   \:  \displaystyle \tt :  \implies  \:  \frac{ - 2m + 8}{m - 10}  =  \frac{ - 54}{69}

 \:  \:  \\ \:  \:  \:  \:  \:  \:  \:\displaystyle \tt  :  \implies \:  \frac{ - 2m + 8}{m - 10}  =  \cancel \frac{ - 54}{69}  \frac{18}{23}

 \:  \: \: \: \: \:  \:  \displaystyle \tt :  \implies \: -  23( - 2m + 8) = 18(m - 10)

 \\   \: \: \:\: \: \: \:\displaystyle \tt :  \implies \: 46m - 184 = 18m - 180

 \:  \: \: \: \: \:  \:  \:\displaystyle \tt :  \implies \: 46m - 184 - 18m + 180 = 0

 \:  \: \: \:  \:  \:\: \: \: \:  \: \: \\ \  \: \: \: \:  \: \:\displaystyle \tt :  \implies \: 28m - 4 = 0

 \:  \:  \: \: \:  \:  \: \\ \:  \: \displaystyle \tt :  \implies \: 28m = 4

 \:    \: \:  \: \\  \:  \: \ \:  \displaystyle \tt :  \implies \: m =  \frac{4}{28}

 \:           \: \\ \: \:  \:   \:  \displaystyle \tt :  \implies \: m =  \color{red}  \cancel\frac{4}{28}  \frac{2}{14} =  \frac{1}{7}

 \: \:    \: \\  \:  \:  \:  \:   \:  \ \:  \displaystyle \tt  :  \implies \:   \color{blue} \boxed{ \frac{1}{7} }

 \:  \:  \blue \bigstar \green{\bold  { \boxed{ \underline{ \bf \: the \: answer \: will \: be \:  \frac{1}{7} }}}}

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