solve this equation using quadratic formula x 2 -4ax+4a 2 -b 2
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x²-4ax+(4a²-b²) = 0
x²-4ax+[(2a)²-(b)²] = 0
x²-4ax+[(2a+b)(2a-b)]=0
x²-(2a+b)x - (2a-b)x +[(2a+b)(2a-b)]=0
x[x-2a-b] - (2a-b)[x-2a-b] = 0
(x-2a+b)(x-2a-b) = 0
x = 2a-b or x = 2a + b
x²-4ax+[(2a)²-(b)²] = 0
x²-4ax+[(2a+b)(2a-b)]=0
x²-(2a+b)x - (2a-b)x +[(2a+b)(2a-b)]=0
x[x-2a-b] - (2a-b)[x-2a-b] = 0
(x-2a+b)(x-2a-b) = 0
x = 2a-b or x = 2a + b
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