solve this equation using substitution method :-
x+5 = 3 (y+5)
x-5 = 7 (y-5)
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Hi !
x + 5 = 3y + 15
x = 3y + 15 - 5
Substitute this value in equ. [ 1]
x = 3y +10
x - 5 = 7y - 35 ----> [ 1 ]
3y + 10 - 5 = 7y - 35
3y + 5 = 7y - 35
5 + 35 = 7y - 3y
40 = 4y
y = 40/4
y = 10
We have now got the value of y
x = 3y + 10
= 3 x 10 + 10
= 30 + 10
= 40
x + 5 = 3y + 15
x = 3y + 15 - 5
Substitute this value in equ. [ 1]
x = 3y +10
x - 5 = 7y - 35 ----> [ 1 ]
3y + 10 - 5 = 7y - 35
3y + 5 = 7y - 35
5 + 35 = 7y - 3y
40 = 4y
y = 40/4
y = 10
We have now got the value of y
x = 3y + 10
= 3 x 10 + 10
= 30 + 10
= 40
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