Question

Solve this equation ......?.........
Value for m

Answer 1

Hey mate here we go

$lets \: write \: eq \\ \frac{x(x - 1) - (m + 1)}{(x - 1)(m - 1)} = \frac{x}{m} \\ cross \: multiplication \\ m(x(x - 1) -(m + 1)) \\ = x((x - 1)(m - 1)) \\ \\ m {x}^{2} - mx - {m}^{2} - m \\ = {x}^{2}m - {x}^{2} - xm + x \\ now \: canclation \: both \: side \: we \: will \: have \: \\ - {m}^{2} - m = - {x}^{2} + x \\ - m(m +1) = - x(x - 1) \\ \\ therefore \: \\ - m(m + 1) = 0 \\ - m = 0 \: \: \: \: \: \: \: \: \: (m + 1 = 0 \: \: \: m = - 1) \\ \\ - x(x - 1) = 0 \\ - x = 0 \: \: \: \: x - 1 = 0 \: \: \: \: x = 1$

I hope this will helps you

mark my ans as brainliest

Answer 2

Answer:

m = -1/2

Step-by-step explanation:

( x(x - 1) - (m + 1))/ (x - 1)(m - 1) = x/m

=> mx(x-1) - m(m+1) = x(x-1)(m-1)

=> x(x-1)(m-(m-1) - m(m+1) = 0

=> x(x-1) - m(m+1) = 0

=> x² - x  - m(m+1) = 0

roots are equal if

D = 0 = b² - 4ac

(-1)² - 4(1)(-m(m+1)) = 0

=> 1 + 4m² + 4m = 0

=> 4m² + 2m + 2m + 1 = 0

=> 2m(2m +1) + 1(2m+1) = 0

=> (2m+1)² = 0

=> m = -1/2