solve this equation
(x-2)(y +5)=(x-1) (y+2)
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Answer:
3x-y-8=0
Step-by-step explanation:
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Explanation
- (x-2)(y+5) = (x-1)(y+2)
By binomial method,
x(y+5) - 2(y+5) = x(y+2) - 1(y+2)
xy+5x - (2y+10) = xy+2x - (y+2)
Opening brackets,
xy+5x-2y-10 = xy+2x-y-2
Cancelling xy on both the sides,
5x-2y-10 = 2x-y-2
Shifting x and y,
5x-2y-2x+y = -2+10
3x-y = 8
.:. 3x-y-8
- (x-2)(y+5) = (x-1)(y+2)
By binomial method,
x(y+5) - 2(y+5) = x(y+2) - 1(y+2)
xy+5x - (2y+10) = xy+2x - (y+2)
Opening brackets,
xy+5x-2y-10 = xy+2x-y-2
Cancelling xy on both the sides,
5x-2y-10 = 2x-y-2
Shifting x and y,
5x-2y-2x+y = -2+10
3x-y = 8
.:. 3x-y-8
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