solve this equation
x^+(x+3)^=117
Answers
Answer:
hope its helpful
Explanation:
Step 1 :Equation at the end of step 1
x • (x + 3) - 117 = 0
Step 2 :Trying to factor by splitting the middle term
Factoring x2+3x-117
The first term is, x2 its coefficient is 1 .
The middle term is, +3x its coefficient is 3 .
The last term, "the constant", is -117
Step-1 : Multiply the coefficient of the first term by the constant 1 • -117 = -117
Step-2 : Find two factors of -117 whose sum equals the coefficient of the middle term, which is 3 .
-117 + 1 = -116
-39 + 3 = -36
-13 + 9 = -4
-9 + 13 = 4
-3 + 39 = 36
-1 + 117 = 116
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
x2 + 3x - 117 = 0
Step 3 :
Parabola, Finding the Vertex:
Find the Vertex of y = x2+3x-117
Explanation:
Answer:
hope its helpful
Explanation:
Step 1 :Equation at the end of step 1
x • (x + 3) - 117 = 0
Step 2 :Trying to factor by splitting the middle term
Factoring x2+3x-117
The first term is, x2 its coefficient is 1 .
The middle term is, +3x its coefficient is 3 .
The last term, "the constant", is -117
Step-1 : Multiply the coefficient of the first term by the constant 1 • -117 = -117
Step-2 : Find two factors of -117 whose sum equals the coefficient of the middle term, which is 3 .
-117 + 1 = -116
-39 + 3 = -36
-13 + 9 = -4
-9 + 13 = 4
-3 + 39 = 36
-1 + 117 = 116
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
x2 + 3x - 117 = 0
Step 3 :
Parabola, Finding the Vertex:
Find the Vertex of y = x2+3x-117