Math, asked by arpitsharma1237, 4 months ago

solve this equation=x(x-3)+2=0
please is equation ka answer acche tarah ase bhejne.jo samaj aa gaya full explanation ke sath​

Answers

Answered by 7991159100s
6

x(x + 3) + 2 = 0 \\  {x}^{2}  + 3x + 2 = 0 \\  {x}^{2}  + x + 2x + 2 = 0 \\ x(x + 1) + 2(x + 1) = 0 \\ (x + 2)(x + 1) = 0 \\  \\  \\  \\  \\

x+2=0

x=-2

x+1=0

x=-1

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Answered by Mrjaiswal09
0

Step-by-step explanation:

x(x - 3)+ 2 = 0 \\ x(x - 3)  + 2=  0 \\ x \times x - x \times 3  + 2=  0 \\  {x}^{2}  - 3x + 2 =  0 \\  {x}^{2}  - (2 + 1)x + 2 = 0 \\  {x}^{2}  - 2x - x + 2 = 0 \\ x(x - 2) - 1(x -2) = 0 \\ (x - 2)(x - 1) = 0 \\  \\ (x - 2) = 0  \:  \:  \:  \:  \:  \:  \: (x - 1) = 0\\ x = 2 \:  \:  \:  \:  \:  \:  \: x = 1 \\ value \: of \: x \:  = 1 \: and2

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