solve this equation
x+y=3
x+z=2
z+x=1
x-y-z=15
get answer of x,y,z
fast
DeekshitSuthar:
sorry mistake in question
x+z is not 2 it is y+z =2
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is dat linear equation in two variables???if it is so then....
a).x+y=3
let x be 0,then,
x+y=3 gives
0+y=3
y=3-0
y=3
hence the equation will be (x,y)=(0,3)
b).x+z=2
let z be 0,then,
x+z=2
x+0=2
x=2-0
x=2
hence the equation will be..(x,y)=(2,0)
c).z+x=1
let z be 0,then,
0+x=1
x=1-0
x=1
hence the equation will be,(x, y)=(1,0)
a).x+y=3
let x be 0,then,
x+y=3 gives
0+y=3
y=3-0
y=3
hence the equation will be (x,y)=(0,3)
b).x+z=2
let z be 0,then,
x+z=2
x+0=2
x=2-0
x=2
hence the equation will be..(x,y)=(2,0)
c).z+x=1
let z be 0,then,
0+x=1
x=1-0
x=1
hence the equation will be,(x, y)=(1,0)
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