Math, asked by mahendrapal899pav6ez, 1 year ago

solve this equation: y+6÷4+y-3÷5=5y-4÷8

Answers

Answered by sanya55
263
Heya!!Here is your answer friend ⤵⤵

 \frac{y + 6}{4}  +  \frac{y - 3}{5}  =  \frac{5y - 4}{8}  \\  \frac{5(y + 6) + 4(y - 3)}{20}  =  \frac{5y - 4}{8}  \\  \frac{5y + 30 + 4y - 12}{20}  =  \frac{5y - 4}{8}   \\  \frac{9y + 18}{20}  =  \frac{5y - 4}{8}  \\ cross \: multiplying \: lhs \: and \: rhs \\ 8(9y + 18) = 20(5y - 4) \\ 72y + 144 = 100y - 80 \\ 100y - 72y = 144 + 80 \\ 28y = 224 \\ y =  \frac{224}{28}  =  \frac{32}{4}  \\ y =  8
Hope it helps you ✌✌
Answered by AasthaSood
74

Step-by-step explanation:

Please refer the attachment

Attachments:
Similar questions