Question

Solve this equivalent resistance question​

Answer 1

R1=5Ω, R2=3Ω, R3=4Ω, R4=1Ω, R5=2Ω

Possible Answers:

15Ω

878Ω

758Ω

7Ω

538Ω

Correct answer:

878Ω

Explanation:

First we need to condense R3 and R4. They are in series, so we can simply add them to get:

R34=5Ω

Now we can condense R2 and R34. They are in parallel, so we will use the following equation:

1Req=∑1R=13+15=815

Therefore:

Req=158

The equivalent circuit now looks like:

Circuit_1.1

Since everything is in series, we can simply add everything up:

Rtotal=R1+Req+R5=5Ω+158Ω+2Ω

Rtotal=878Ω