Solve this exponents question with full solution
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Yes , this a really tricky one , but it will be easy if you know the method
3−2✓2–√−−−−−−−√
To remove the outer square root , we will the thing inside as a perfect square
We know , (a−b)2=a2−2ab+b2
3−22–√=2+1−22–√
which is (2–√)2−2⋅1⋅2–√+12
We can relate the values by the identity. here a=2–√,b=1
So therefore 3−22–√=(2–√−1)2
So 3−22–√−−−−−−−√=(2–√−1)2−−−−−−−−√
=2–√−1 (since square roots should always give the positive value)
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