solve this ........ faat
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In ∆ADB, AO is the median. (Diagonals bisect)
ar (∆ADO) = ar (∆ABO) - (1)
In ∆PDB, PO the median
ar (∆PDO) = ar (∆PBO) - (2)
(1) - (2)
ar (∆ADO) - ar (∆PDO) = ar (∆ABO) - ar (∆PBO)
ar (∆ADP) = ar (∆ABP)
ar (∆ADO) = ar (∆ABO) - (1)
In ∆PDB, PO the median
ar (∆PDO) = ar (∆PBO) - (2)
(1) - (2)
ar (∆ADO) - ar (∆PDO) = ar (∆ABO) - ar (∆PBO)
ar (∆ADP) = ar (∆ABP)
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