solve this factorization
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p=1 and P=3/4 because 4p(p2-1)-3(p-1)
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Heya User,
--> 4p³ - 7p + 3 = ( p - 1 )( 4p² + 4p - 3 )
= ( p - 1 )( 2p - 1 )( 2p + 3 )
--> 8a³ + 4a - 3 = ( 2a - 1 )( 4a² + 2a + 3 )
[ Cannot be further factorized =_= ]
Hope this helps ^_^
--> 4p³ - 7p + 3 = ( p - 1 )( 4p² + 4p - 3 )
= ( p - 1 )( 2p - 1 )( 2p + 3 )
--> 8a³ + 4a - 3 = ( 2a - 1 )( 4a² + 2a + 3 )
[ Cannot be further factorized =_= ]
Hope this helps ^_^
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