Question

Solve this fast!!!
I’ll mark you brainliest

Answer 1

Answer;

consider the four boxes as A,B and C,D

so,

A+B=16___eqn 1

A+C=26__eqn 2

B+D=16__eqn 3

C-D=12 __eqn 4

Adding eqn 1and 4 , and Adding eqn 2 and 3.

~ A+B = 16__eqn 1

(+) C-D =12__eqn 4

A+B+C-D= 28___eqn5

~ A+C = 26___eqn 2

(+) B+ D =16___eqn 3

A +B + C +D = 42___eqn6

Subtracting eqn 6 from 5,

so,

A+B+C-D=28__eqn 5

(-) A+B+C+D=42__eqn 6

-2d= -14

D=-14

-2

D=7

# taking D, we will solve the other and find A,B,C,D,

B+D =16

B+7=16

B=16-7

B=9

A+B=16

A+9=16

A=16-9

A=7

A+C=26

7+ C=26

C=26-7

C=19

we are done!

so here ,

A=7

B=9

C=19

D=7

MARK AS BRAIBLIEST PLEEEAASEEE.