Math, asked by krishnaagrawal2835, 4 days ago

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Answered by vishannu05
1

Answer:

Ncert solutions

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Mathematics

Science

Chapters in NCERT Solutions - Mathematics, Class 7

Exercises in Perimeter and Area

Question 10

Q5) PQRS is a parallelogram (Fig 11.23). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:

(a) the area of the parallelogram PQRS

(b) QN, if PS = 8 cm

Solution

Transcript

Solution:

(a) Area of the parallelogram PQRS

=SR\times QM\left(Area\ =\ Base\times Height\right)

=12cm\times7.6cm

=91.2cm^2

(b) Area of the parallelogram PQRS

=\frac{1}{2}\times PS\times QN

91.2cm^2=\frac{1}{2}\times8cm\times QN

QN=\frac{91.2\times2}{8}=22.8cm

Step-by-step explanation:

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Answered by subhrajit15
0

Area of the parallelogram =

base×height

= PS×QM = SR×QN

or, 24× QM = 16×9

or, QM = 6 cm (Ans)

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