Solve this fast please
Answers
Answer:
624m²
Step-by-step explanation:
On observing the figure, we can tell that the area of the shaded part/path is equal to the area of EFGH subtracted from the area of ABCD.
So let's try to find the area of both the rectangles first.
From the figure for the rectangle ABCD:
Length = 60m
Breadth = 100m
⇒ Area of ABCD = Length × Breadth
⇒ Area of ABCD = 60 × 100
⇒ Area of ABCD = 6000m²
From the figure for the rectangle EFGH:
Since we don't know the Length and the Breadth of the inner rectangle, let's find it out now.
[The path width is 2m throughout as per the data given in the question]
Length:
Length = AB - [Width between BC and FG + Width between AD and EH]
Length = AB - [2 + 2]
Length = 60 - [4]
Length = 56m
Breadth:
Breadth = AD - [Width between AB and EF + Width between CD and GH]
Breadth = AD - [2 + 2]
Breadth = 100 - [2 + 2]
Breadth = 100 - [4]
Breadth = 96m
⇒ Area of EFGH = Length × Breadth
⇒ Area of EFGH = 56 × 96
⇒ Area of EFGH = 5376m²
Now that we've got both the areas of the rectangles, let's find out the area of the path.
⇒ Area of the path = ar(ABCD) - ar(EFGH)
⇒ Area of the path = 6000 - 5376
⇒ Area of the path = 624m²
Hence solved.
Answer:
Answer:
624m²
Step-by-step explanation:
On observing the figure, we can tell that the area of the shaded part/path is equal to the area of EFGH subtracted from the area of ABCD.
So let's try to find the area of both the rectangles first.
From the figure for the rectangle ABCD:
Length = 60m
Breadth = 100m
⇒ Area of ABCD = Length × Breadth
⇒ Area of ABCD = 60 × 100
⇒ Area of ABCD = 6000m²
From the figure for the rectangle EFGH:
Since we don't know the Length and the Breadth of the inner rectangle, let's find it out now.
[The path width is 2m throughout as per the data given in the question]
Length:
Length = AB - [Width between BC and FG + Width between AD and EH]
Length = AB - [2 + 2]
Length = 60 - [4]
Length = 56m
Breadth:
Breadth = AD - [Width between AB and EF + Width between CD and GH]
Breadth = AD - [2 + 2]
Breadth = 100 - [2 + 2]
Breadth = 100 - [4]
Breadth = 96m
⇒ Area of EFGH = Length × Breadth
⇒ Area of EFGH = 56 × 96
⇒ Area of EFGH = 5376m²
Now that we've got both the areas of the rectangles, let's find out the area of the path.
⇒ Area of the path = ar(ABCD) - ar(EFGH)
⇒ Area of the path = 6000 - 5376
⇒ Area of the path = 624m²
Hence solved.