Math, asked by hehjzbdbhehe, 3 months ago

Solve this fast please​

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Answered by Tomboyish44
33

Answer:

624m²

Step-by-step explanation:

On observing the figure, we can tell that the area of the shaded part/path is equal to the area of EFGH subtracted from the area of ABCD.

So let's try to find the area of both the rectangles first.

From the figure for the rectangle ABCD:

Length = 60m

Breadth = 100m

⇒ Area of ABCD = Length × Breadth

⇒ Area of ABCD = 60 × 100

Area of ABCD = 6000m²

From the figure for the rectangle EFGH:

Since we don't know the Length and the Breadth of the inner rectangle, let's find it out now.

[The path width is 2m throughout as per the data given in the question]

Length:

Length = AB - [Width between BC and FG + Width between AD and EH]

Length = AB - [2 + 2]

Length = 60 - [4]

Length = 56m

Breadth:

Breadth = AD - [Width between AB and EF + Width between CD and GH]

Breadth = AD - [2 + 2]

Breadth = 100 - [2 + 2]

Breadth = 100 - [4]

Breadth = 96m

⇒ Area of EFGH = Length × Breadth

⇒ Area of EFGH = 56 × 96

Area of EFGH = 5376m²

Now that we've got both the areas of the rectangles, let's find out the area of the path.

⇒ Area of the path = ar(ABCD) - ar(EFGH)

⇒ Area of the path = 6000 - 5376

Area of the path = 624m²

Hence solved.

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Answered by XxitsmrseenuxX
0

Answer:

Answer:

624m²

Step-by-step explanation:

On observing the figure, we can tell that the area of the shaded part/path is equal to the area of EFGH subtracted from the area of ABCD.

So let's try to find the area of both the rectangles first.

From the figure for the rectangle ABCD:

Length = 60m

Breadth = 100m

⇒ Area of ABCD = Length × Breadth

⇒ Area of ABCD = 60 × 100

⇒ Area of ABCD = 6000m²

From the figure for the rectangle EFGH:

Since we don't know the Length and the Breadth of the inner rectangle, let's find it out now.

[The path width is 2m throughout as per the data given in the question]

Length:

Length = AB - [Width between BC and FG + Width between AD and EH]

Length = AB - [2 + 2]

Length = 60 - [4]

Length = 56m

Breadth:

Breadth = AD - [Width between AB and EF + Width between CD and GH]

Breadth = AD - [2 + 2]

Breadth = 100 - [2 + 2]

Breadth = 100 - [4]

Breadth = 96m

⇒ Area of EFGH = Length × Breadth

⇒ Area of EFGH = 56 × 96

⇒ Area of EFGH = 5376m²

Now that we've got both the areas of the rectangles, let's find out the area of the path.

⇒ Area of the path = ar(ABCD) - ar(EFGH)

⇒ Area of the path = 6000 - 5376

⇒ Area of the path = 624m²

Hence solved.

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