Question

solve this fast
Thank you to those who help me​

Answer 1

$\huge\blue{\boxed{\mathfrak{refer \: the \: attachment }}}$

Steps Followed

• Simplify LHS and RHS seperately

• Change tanA in the form of sinA and cosA using identity

$tana = \frac{sina}{cosa}$

• Change secA in the form of cosA using the identity

$seca = \frac{1}{cosa}$

• Cut cosA with cosA now take LCM

• now cut sinA with sinA

• Now only 2/sinA left change sinA in the form of cosecA using identity

$coseca = \frac{1}{sina}$

• Now your LHS is 2cosecA

• RHS is already 2cosecA

• LHS = RHS

• Hence proved

Answer 2

LHS=RHS

Hence proved

Tushar here