solve this fast this question is from class 10 cbse
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Step-by-step explanation:
sec37/cosec(90-37,o;uhnggggggggg
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the ans of the que is 0 where sec37/cosec37 is 1
2cot15cot25cot75cit64cot45 is 2and 3(sin^2 18 + sin^2 72) is 3
then you will get
the terms as
1+2-3 which is equal to 0
2cot15cot25cot75cit64cot45 is 2and 3(sin^2 18 + sin^2 72) is 3
then you will get
the terms as
1+2-3 which is equal to 0
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