Question

solve this fast with full process​

Answer 1

Answer:

As the second body goes up and comes down and meets the first body, the displacement of the second body is same as that of the first body.

And also when the second body reaches the point of projection, its speed will be same as the speed of projection, let it be u.

For first body, initial speed is zero

Explanation:

v²=2gh

for second body

v²-u²=-2gh

from these two equations

2v²-u²=0

u=2√v.

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Answer 2

$\huge\bold\red{Answer:-}$

ᴜʀ ᴀɴsᴡᴇʀ ɪs

$v \sqrt{2}$

ᴇxᴘʟᴀɴᴀᴛɪᴏɴs:-

ᴀs ᴛʜᴇ sᴇᴄᴏɴᴅ ʙᴏᴅʏ ɢᴏᴇs ᴜᴘ ᴀɴᴅ ᴄᴏᴍᴇs ᴅᴏᴡɴ ᴀɴᴅ ᴍᴇᴇᴛ ᴛʜᴇ ғɪʀsᴛ ʙᴏᴅʏ,ᴛʜᴇ ᴅɪsᴘʟᴀᴄᴇᴍᴇɴᴛ ᴏғ sᴇᴄᴏɴᴅ ʙᴏᴅʏ ɪs sᴀᴍᴇ ᴀs ᴛʜᴀᴛ ᴏғ ᴛʜᴇ ғɪʀsᴛ ʙᴏᴅʏ ᴀɴᴅ ᴀʟsᴏ ᴡʜᴇɴ ᴛʜᴇ sᴇᴄᴏɴᴅ ʙᴏᴅʏ ʀᴇᴀᴄʜᴇs ᴛʜᴇ ᴘᴏɪɴᴛ ᴏғ ᴘʀᴏᴊᴇᴄᴛɪᴏɴs,ɪᴛs sᴘᴇᴇᴅ ᴡɪʟʟ ʙᴇ sᴀᴍᴇ ᴀs ᴛʜᴇ sᴘᴇᴇᴅ ᴏғ ᴘʀᴏᴊᴇᴄᴛɪᴏɴ,ʟᴇᴛ ɪᴛ ʙᴇ ᴜ ғᴏʀ ғɪʀsᴛ ʙᴏᴅʏ,ɪɴɪᴛɪᴀʟ sᴘᴇᴇᴄʜ ɪs ᴢᴇʀᴏ

${v}^{2} = 2gh \\ for \: second \: body \\ {v}^{2} - {u}^{2} = - 2gh \\ from \: these \: two \: equations \: \\ 2 {v}^{2} - {u}^{2} = 0 \\ = u = 2 \sqrt{v}$