solve this. Find the length of OP
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put sin 30°=1/2 . n u'll get the answer OP=2a.
Hope it helps...
Hope it helps...
midhatamil:
can u completely solved it . nd then snd to me plzx
can u completely solved it . nd then snd to me plzz
i can't give it now...but i'll certainly send it today itself!
okk no plbm thank i will try my self
Answered by
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In ΔAOP and ΔBOP
AP = BP (Tangents)
OP = OP (Common)
OA = OB (Radius)
ΔAOP congruent ΔBOP (By S-S-S Criterion)
∠OPA = ∠OPB (Corres. parts )
And
∠OPA + ∠OPB = ∠APB
= ∠OPA + ∠OPA = 60°
= 2∠OPA = 60°
= ∠OPA = 30°
Also, OA perpendicular to AP (Tangent drawn at any point on the circle is perpendicular to the radius at the point of contact)
In ΔOAP,
As OA = radius of circle = a
Therefore,
OP = 2a
AP = BP (Tangents)
OP = OP (Common)
OA = OB (Radius)
ΔAOP congruent ΔBOP (By S-S-S Criterion)
∠OPA = ∠OPB (Corres. parts )
And
∠OPA + ∠OPB = ∠APB
= ∠OPA + ∠OPA = 60°
= 2∠OPA = 60°
= ∠OPA = 30°
Also, OA perpendicular to AP (Tangent drawn at any point on the circle is perpendicular to the radius at the point of contact)
In ΔOAP,
As OA = radius of circle = a
Therefore,
OP = 2a
Sorry m not able to appload the diagram
it okk I'm understand clearly this question thank a lot ☺
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