Question

Solve this .....

find the perimeter of triangle if its area is 9 cm^2 and perpendicular ² + breadth² is 45.​

Answer 1

Given,

Area of traingle =$\frac {1}{2} Base * height$

\ ⟹ 1/2 × base × height = 9

\ ⟹ base × height = 18

As , given

\ ⟹ perpendicular ² + base² = 45

\ ⟹ Apply, (P + B )² = p² + B² + 2B× H

\ ⟹ (P + B)² = 45 + 2(18)

\ ⟹ (P + B)² = 45 + 36

\ ⟹ (P + B)² = 81

\ ⟹ (P + B) = √81 = 9

\ ⟹ So, Here we have to check the digits which makes sum 9

➡ 6 and 3 = 9

\ ⟹ Probably 6 and 3 are its base and perpendicular of the traingle.

Answer 2

$\Large {\mathfrak {Solution :}}$