Question

solve this. find the value of the discrimination

Answer 1

D = b2 - 4ac
Here,
a= 1
b=4
c=1

D=(4)2 - 4 (1)(1)
D =8 -4
D=4

D>0 so the roots are real and distinct.
Mark as brainliest if helpful!

Answer 2

${x}^{2} + 4x + 1 = 0$
$\\ d = {b}^{2} - 4ac$
a=1, b=4,c=1

${4}^{2} - 4 \times 1 \times 1 \\ d=16 - 4 \\ d= 12$

As the discriminant is greater than zero it means that the equation has two distinct real roots.