Question

Solve this for 100 points and take brainiest mark and do fast

Answer 1

hoping these answers are useful

Answer 2

Answer:

pls mark as brainliest

Step-by-step explanation:

let us consider a triangle right angled.

AB=c

BC=a

AC=b

by pythogorean theorem

BC^2=AB^2+AC^2

b^2=a^2+c^2

b=sqrt(a^2+c^2)

now sinA=opposite side/hypotenuse

sinA=BC/AC

=a/b

=a/sqrt(a^2+c^2)

squaring on both sides

sin^2A=a^2/(a^2+c^2)

cosA=AB/AC

=c/sqrt(a^2+c^2)

cos^2A=c^2/a^2+c^2

sin^2A+cos^2A=a^2+c^2/a^2+c^2=1=RHS

3. AB=24

AC=25

BC=7

sinC=AB/AC

sinC=24/25

cosA=BC/AC=7/25

tanA=opposite side/adjacent side

=BC/AB

=7/24

cosC=BC/AC=7/25