Math, asked by sindhusharavuri, 1 year ago

solve this for 15 points!!!!!!

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Angel291: hey Sindhu why u block me

Answers

Answered by abhi178

let P and r are the roots of given polynomial ,

ax² -5 x + c =0

sum of roots = -coefficient of x/coefficient of x² = 5/a

products of roots = constant /coefficient of x² = c/a

a/c to question,
sum of roots = 10
5/a = 10
a = 1/2

products of roots = 10

c/a = 10

c/(1/2) = 10

c = 5

abhi178: where sir , i am not write some of roots = x²

abhi178: i write sum of roots =- coefficient of x/coefficient of x²

abhi178: e.g 5/a = 10 so, a = 1 /2

abhi178: in the same way for product i wrote

abhi178: am i wrong sir

mysticd: I'm sry abhi

mysticd: it is my mistake.

mysticd: u'r solution is correct

abhi178: it's okay sir , don't say sorry

Answered by jatinsaini1140

Answer:

let P and r are the roots of given polynomial ,

ax² -5 x + c =0

sum of roots = -coefficient of x/coefficient of x² = 5/a

products of roots = constant /coefficient of x² = c/a

a/c to question,

sum of roots = 10

5/a = 10

a = 1/2

products of roots = 10

c/a = 10

c/(1/2) = 10

c = 5

Step-by-step explanation:

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